Issue
This Content is from Stack Overflow. Question asked by dudebro
I have an enum:
#[derive(Serialize, Deserialize)]
enum Action {
Join,
Leave,
}
and a struct:
#[derive(Serialize, Deserialize)]
struct Message {
action: Action,
}
and I pass a JSON string:
"{"action":0}" // `json_string` var
but when I try deserialzing this like this:
let msg: Message = serde_json::from_str(json_string)?;
I get the error expected value at line 1 column 11
.
In the JSON if I were to replace the number 0
with the string "Join"
it works, but I want the number to correspond to the Action
enum’s values (0
is Action::Join
, 1
is Action::Leave
) since its coming from a TypeScript request. Is there a simple way to achieve this?
Solution
You want serde_repr
!
Here’s example code from the library’s README:
use serde_repr::{Serialize_repr, Deserialize_repr};
#[derive(Serialize_repr, Deserialize_repr, PartialEq, Debug)]
#[repr(u8)]
enum SmallPrime {
Two = 2,
Three = 3,
Five = 5,
Seven = 7,
}
fn main() -> serde_json::Result<()> {
let j = serde_json::to_string(&SmallPrime::Seven)?;
assert_eq!(j, "7");
let p: SmallPrime = serde_json::from_str("2")?;
assert_eq!(p, SmallPrime::Two);
Ok(())
}
For your case:
use serde_repr::{Serialize_repr, Deserialize_repr};
#[derive(Serialize_repr, Deserialize_repr)]
#[repr(u8)]
enum Action {
Join = 0,
Leave = 1,
}
use serde::{Serialize, Deserialize};
#[derive(Serialize, Deserialize)]
struct Message {
action: Action,
}
This Question was asked in StackOverflow by dudebro and Answered by wisha It is licensed under the terms of CC BY-SA 2.5. - CC BY-SA 3.0. - CC BY-SA 4.0.