[SOLVED] Nim: How to pass an array of varying size to an argument of a foreign function calling into a .dll?


This Content is from Stack Overflow. Question asked by Joshua Fenner

Bellow is a minimal example when wrapping the OpenAL32.dll. The foreign function alcCreateContext has the argument attrlist which takes a ptr to an array of type ALCint or nil. The issue is the array can be of different lengths depending on the amount of different flags passed in. The array should be organized as [flag, int, flag, int, …]. How can this be accomplished in a more dynamic way allowing the inclusion of ALC_FREQUENCY for example? The array size is currently hard coded into the procedure and its nasty.

when defined(windows):
  {.push cdecl, dynlib: "OpenAL32.dll", importc.}
  {.push importc.}

  ALCint = cint
  ALCdevice* = pointer
  ALCcontext* = pointer

  ALC_MONO_SOURCES* = 0x00001010
  ALC_STEREO_SOURCES* = 0x00001011
  ALC_FREQUENCY* = 0x00001007

proc alcCreateContext*(device: ALCdevice; attrlist: ptr array[0..3, ALCint]): ALCcontext
proc alcOpenDevice*(devicename: cstring): ALCdevice

discard alcOpenDevice(nil).alcCreateContext([ALC_MONO_SOURCES.ALCint, 65536.ALCint, ALC_STEREO_SOURCES.ALCint, 65536.ALCint].unsafeAddr)

I experimented with openArray and other containers. Is the solution some sort of cast? This is also the workaround for getting more then 256 sounds out of OpenAL.


An array in C is simply a pointer to anywhere with one or more contiguous elements of the same type. So to pass a C array to a function you simply need to get such a pointer. Say for example you have a seq of integers then the address of the first element is a C array. Simply do mySeq[0].addr and you’re good. Keep the lifecycle of the data in mind though. If Nim doesn’t find any more references to the sequence then the memory will get freed. You can also manually get a pointer with create (https://nim-lang.org/docs/system.html#create%2Ctypedesc) and you can cast such pointers to ptr UncheckedArray[T] to be able to use [] on the data in Nim.

This Question was asked in StackOverflow by Joshua Fenner and Answered by PMunch It is licensed under the terms of CC BY-SA 2.5. - CC BY-SA 3.0. - CC BY-SA 4.0.

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