# Issue

This Content is from Stack Overflow. Question asked by INM

How can I change this part `[AIF,j]=get_AIF_j(InterpFact)` and `[~,j_index] = min(InterpFact-AIF_vect)`
correctly ? and what about the remaining code? Thanks in advance..

``````%Matlab code
InterpFact = (fs_h/2/2)/(fd_max);
[AIF,j]=get_AIF_j(InterpFact);

function [AIF,j] = get_AIF_j (InterpFact)
j_vect = 1:10;
AIF_vect = floor(j_vect*InterpFact)./j_vect;
[~,j_index] = min(InterpFact-AIF_vect);
j = j_vect(j_index);
AIF = AIF_vect(j_index);
end

#Python code
InterpFact = (fs_h/2/2)/(fd_max)
[AIF,j]=get_AIF_j(InterpFact)

def get_AIF_j (InterpFact):
j_vect =np.arange(1,11)
AIF_vect = np.floor(j_vect*InterpFact)/j_vect
[~,j_index] = min(InterpFact-AIF_vect)
j = j_vect[j_index]
AIF = AIF_vect[j_index];
return AIF,j
``````

# Solution

This MATLAB:

``````[~,j_index] = min(InterpFact-AIF_vect);
``````

would be translated to Python as:

``````j_index = np.argmin(InterpFact-AIF_vect)
``````

Also, `…/(fd_max)` can only be translated the way you did if `fd_max` is a scalar. A division with a matrix in MATLAB solves a system of linear equations.

I strongly recommend that you run the two pieces of code side by side with the same input, to verify that they do the same thing. You cannot go by guesses as to what a piece of code does.

``` This Question was asked in  StackOverflow by  Mario and Answered by Cris Luengo It is licensed under the terms of
CC BY-SA 2.5. - CC BY-SA 3.0. - CC BY-SA 4.0.```
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