[SOLVED] Can’t get neat to automatize jump


This Content is from Stack Overflow. Question asked by ikiwq

i am trying to re-create the dino game from Chrome and automatize it using neat.

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The dinosaur has a fixed X position and can only jump.
The obstacles move towards the player are procedurally generated: i have a queue containing all the obstacles and when the x position of the last one has reached a certain position, a function generates another obstacle. If the first obstacle has gone too left, it gets popped, so the next one becomes the first.

The game is contained inside a Game() class. The constructor calls a reset function that creates an array for all the dinos controlled by the AI, the genomes and the networks.

def Reset(self, genomes, config):

    self.nets = []
    self.ge = []
    self.dinos = []

    for n, g in genomes:
        net = neat.nn.FeedForwardNetwork.create(g, config)

        dino = Dino()

        g.fitness = 0


In the update loop, i iterate through each remaning dino and i add a score to them. The output of the network is processed by giving it the dino x position, the x position of the first obstacle in the Queue and a bool that stes if the dino can jump or not. I also check the collision between the dinos and the obstacles. If the dino collides, his fitness score is lowered and is deleted from the game.

def update(self):

    for x, dino in enumerate(self.dinos):
        self.ge[x].fitness += 0.1
        output = self.nets[x].activate((dino.x, self.obstacleQueue.queue[0].rect.x, dino.canJump))
        if output[0] > 0.5:
            if dino.canJump:

It actually (sometimes) works as it should: there are some dinos that jump trough the obstacles, but they can’t get past the second.
Then after 2 or 3 generations, they can’t get past the first obstacle.


I actually didn’t check if the dino.canJump value was set correcty, as it was played by an AI and not by an human.
I had to rewrite a bit the code to check if the dino was falling.

This Question was asked in StackOverflow by ikiwq and Answered by ikiwq It is licensed under the terms of CC BY-SA 2.5. - CC BY-SA 3.0. - CC BY-SA 4.0.

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